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Tutors Answer Your Questions about Bodies-in-space (FREE)
Question 1027792: A pile of coal has a rectangular base 50 ft. by 400 ft. If the sides of the pile are all inclined 45 degrees to the horizontal, and the coal weighs 94 lb. per cu. ft., find the number of tons of coal in the pile.
Click here to see answer by Cromlix(4381)  |
Question 1028529: A container is designed in the shape of an open right circular cylinder (bottom but no top). The container is to hold 1248 cc. The base must be cut from the smallest square piece of material and the corners of this piece are then wasted. Assume no other materials need be wasted in construction. Find the height of the container for which the cost of the material used to create it is the minimum possible. Express your answer as a decimal rounded to the nearest hundredth.
Answer: 8.64
So I know it is a rather easy problem given that I must just find the dimesnions. However, I am asked to find the height of the container that would result in the MINIMUM cost/use of material. How do I find the minimum?
Any help is greatly appreciated!! Thank you in advance!
Click here to see answer by mananth(16946)  |
Question 1034801: A sphere of ice cream is placed on your ice cream cone. Both have a diameter of 8 cm. The height of your cone is 12 cm. Will all the ice cream, fit into the cone if it melted? Show all data to support your conclusion.
If no, what would be the diameter of a sphere of ice cream that would fill the cone? (Nearest tenth of a centimeter)
Click here to see answer by Cromlix(4381)  |
Question 872010: a flower vase, in the form of a hexagonal prism, is to be filled with 512 cubic inches of water. find the height of the water if the wet portion of the flower vase and its volume are numerically equal.
Click here to see answer by furryfeg(1) |
Question 1053927: In the figure, a sealed conical vessel of height 10 cm contains some water to a mark M. When it is inverted, the water surface is still at the mark M. Find the ratio of the volume of water to the capacity of the vessel. Then find the height of the mark M above the vertex of the vessel to 3dp.
Thanks!
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 1062745: Marcie purchases a helium tank that contains 7.9 cubic feet of helium. Marcie is making a balloon display that contains 15 spherical balloons with a 6 inch radius.
A: Will the helium tank provide enough helium for the display?
B: Why or why not?
Use the approximation of 3.14 for π in your calculations and round your answer to the nearest tenth if necessary. Hint: convert 6 inches into feet before you begin your calculation.
Select only one answer each for parts A and B.
B: the total volume of the balloons is more than 7.9 cubic feet
A: Yes
A: No
B: the total volume of the balloons is less than 7.9 cubic feet
B: the total volume of the balloons cannot be determined in cubic feet
Click here to see answer by Alan3354(69443)  |
Question 1064392: I have a 6 inch diameter ball. How many balls will fill a room 10ftx12ft with a 8ft ceiling (10x12x8=960)? This room has no furniture or obtrusion's to consider.
I can visualize 8 balls occupying a 1ftx1ftx1ft space if the balls are set in straight rows from one another. 8 balls/cubic foot of space.
8 balls x 960 = 7,680 balls
BUT if I move the second level of balls over so they nestle into the depressed areas found between the first row of balls I am overwhelmed trying to figure that out.
I have looked online and see there is rounded questimate of .74, but I am not sure if this is what I need?
Do I simply take 8 balls/cubic ft x 960 cubic ft divide by .74 = ?
= 10,378 balls
Thanks
Click here to see answer by KMST(5328)  |
Question 1069349: 3. A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round your answer to the nearest tenth of a cubic inch. Use 3.14 to approximate pi. The top is 9 inches and the side is 14 inches.
Click here to see answer by Alan3354(69443)  |
Question 1073781: The diameter of the earth’s orbit around the sun is approximately 186 million miles.
Looking at a star from the two points on the orbit which are furthest apart, the lines of sight
to the star form an angle of 4.269 × 10−4 degrees. How many light-years away is this star
from the earth? Note that one light-year is approximately 5.879 × 1012 miles.
Click here to see answer by ankor@dixie-net.com(22740)  |
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