SOLUTION: A cylindrical can without a top is made to contain 75 in^3 of liquid. Find the dimensions that will minimize the cost of the metal to make the can.

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Question 1189158: A cylindrical can without a top is made to contain 75 in^3 of liquid. Find the dimensions that will minimize the cost of the metal to make the can.
Answer by ikleyn(52781) About Me  (Show Source):
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A cylindrical can without a top is made to contain 75 in^3 of liquid.
Find the dimensions that will minimize the cost of the metal to make the can.
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            The problem is to minimize the surface area of the described cylinder without the top.


As you know, the volume of a cylinder is 

    V = pi%2Ar%5E2%2Ah, 

where pi = 3.14, r is the radius and h is the height.


In your case the volume is fixed:

    pi%2Ar%5E2%2Ah = 75 cubic inches.                          (1)


The surface area of a top-opened cylinder is 

    S = 2pi%2Ar%2Ah + pi%2Ar%5E2,                               (2)

and they ask you to find minimum of (2) under the restriction (1).


You can rewrite the formula (2) in the form

    S(r) = %282%2Api%2Ar%5E2%2Ah%29%2Fr + pi%2Ar%5E2.                         (3)


In formula (3), replace  pi%2Ar%5E2%2Ah  by  75, based on (1). You will get

    S(r) = %282%2A75%29%2Fr + pi%2Ar%5E2 = 150%2Fr + pi%2Ar%5E2.


The plot below shows the function S(r) = 150%2Fr + pi%2Ar%5E2, and you can clearly see that it has the minimum.



    


        Plot y = 150%2Fr + 3.14%2Ar%5E2



To find the minimum, use Calculus: differentiate the function to get

S'(r) = -150%2Fr%5E2 + 2%2Api%2Ar = %28-150+%2B+2pi%2Ar%5E3%29%2Fr%5E2

and equate it to zero.


S'(r) = 0   leads you to equation  2pi%2Ar%5E3 = 150,   which gives 

r = root%283%2C150%2F%282%2Api%29%29 = root%283%2C150%2F%282%2A3.14%29%29 = 2.88 inches (approximately).


Answer.  r = 2.88 inches, h = 75%2F%283.14%2A2.88%5E2%29 = 2.88 inches  give the minimum of the surface area.

Solved.