SOLUTION: A hallow metal sphere 45cm in diameter is as a float. If the metal sphere sinks of the depth of 15cm, what is the area of the wetted surface?

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Question 1189058: A hallow metal sphere 45cm in diameter is as a float. If the metal sphere sinks of the depth of 15cm,
what is the area of the wetted surface?
Answer by ikleyn(52784) About Me  (Show Source):
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A cross%28hallow%29 HOLLOW metal sphere 45cm in diameter is as a float. If the metal sphere sinks of the depth of 15cm,
what is the area of the wetted surface?
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Use the formula for the surface area of a spherical cap

    A = 2%2Api%2AR%2Ah,


where pi = 3.14159...,  R is the sphere radius (45 cm), h is the depth of the spherical cap (15 cm).


According to the formula, the wetted area of the sphere is

    A = 2*3.14159*45*15 = 4241.1465 cm^2    ANSWER

Solved.

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For the area of a spherical segment,  see these Internet sources

https://en.wikipedia.org/wiki/Spherical_segment

https://mathworld.wolfram.com/Zone.html

https://www.math10.com/en/geometry/sphere.html