SOLUTION: A sphere is placed in a cubical container in such way that the faces of the container are tangent to the sphere. The remaining space of the container is filled with one kilogram of

Algebra ->  Bodies-in-space -> SOLUTION: A sphere is placed in a cubical container in such way that the faces of the container are tangent to the sphere. The remaining space of the container is filled with one kilogram of      Log On


   



Question 1189050: A sphere is placed in a cubical container in such way that the faces of the container are tangent to the sphere. The remaining space of the container is filled with one kilogram of water. What is the radius of the sphere?
Found 2 solutions by Alan3354, math_helper:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A sphere is placed in a cubical container in such way that the faces of the container are tangent to the sphere. The remaining space of the container is filled with one kilogram of water. What is the radius of the sphere?
---------------------
1 kg of water is a volume of 1000 cc
---
r = radius of the sphere. Its volume is 4pi%2Ar%5E3%2F3 cc
---
The volume of the cube is (2r)^3 = 8r^3
The space filled by water is 8r%5E3+-4pi%2Ar%5E3%2F3
---
8r%5E3+-4pi%2Ar%5E3%2F3+=+1000
24r%5E3+-+4pi%2Ar%5E3+=+3000
r%5E3+=+3000%2F%2824+-+4pi%29
r%5E3+=+262.38 apx
r =~ 6.4 cms

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Tutor Alan made a small mistake: +r%5E3+=+3000%2F%2824-4pi%29+ = +262.38cm%5E3 resulting in +r+=+6.40cm+ (approx.)