SOLUTION: The ball of a float valve has a diameter of 4 in., and the thickness of the metal is 0.05 in. How much does it weigh if it is made of copper? (Copper weighs 556 lb. per cu. ft.)

Algebra ->  Bodies-in-space -> SOLUTION: The ball of a float valve has a diameter of 4 in., and the thickness of the metal is 0.05 in. How much does it weigh if it is made of copper? (Copper weighs 556 lb. per cu. ft.)      Log On


   



Question 1181645: The ball of a float valve has a diameter of 4 in., and the thickness of the metal is 0.05 in. How much does it weigh if it is made of copper? (Copper weighs 556 lb. per cu. ft.)
Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Outer volume - inner volume = volume of copper.
Volume of copper * density of copper = weight of copper
outer radius = 2 "
inner radius = 2- 0.05 = 1.95 "
Volume of copper= (4/3)*pi * (2-1.95)^3
V= 0.000523 in^3
556 lb/ft^3= 5.15 ounce/in^3
Weight of copper = 0.000523* 5.15
= 0.0027 ounces

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

            The solution by @mananth is  FATALLY  INCORRECT !

            It contains a  FATALL  ERROR !

            If to combine all incorrect solutions/answers by @mananth at this forum,
            it would comprise an entire book showing all possible and typical errors
            and teaching on how  Math problems should not be solved at any circumstances !

            See my correct solution below.


Outer volume - inner volume = volume of copper.

Volume of copper * density of copper = weight of copper

outer radius = R = 2 inches

inner radius = r = 2- 0.05 = 1.95 inches.

Volume of copper = %284%2F3%29%2Api%2AR%5E3 - %284%2F3%29%2Api%2Ar%5E3 = %284%2F3%29%2A3.14%2A2%5E3+-+%284%2F3%29%2A3.14%2A1.95%5E3

V= 2.449 in^3

556 lb/ft^3 = 0.322 lb/in^3

Weight of copper = 2.449 * 0.322 = 0.789 pounds.     ANSWER


            Notice that the correct answer is about 5000 times the incorrect answer by @mananth   ( ! )   ( ! ! )   ( ! ! ! )