SOLUTION: the corners of a cubical block touch the closed spherical shell that encloses it. the volume of the box is 2744 cc. what volume in cc, inside the shell is not occupied by the block

Algebra ->  Bodies-in-space -> SOLUTION: the corners of a cubical block touch the closed spherical shell that encloses it. the volume of the box is 2744 cc. what volume in cc, inside the shell is not occupied by the block      Log On


   



Question 1178405: the corners of a cubical block touch the closed spherical shell that encloses it. the volume of the box is 2744 cc. what volume in cc, inside the shell is not occupied by the block?
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.

The side length of the cube is   a = root%283%2C2744%29 = 14 cm.


The diameters of the sphere is  d = sqrt%2814%5E2%2B14%5E2%2B14%5E2%29 = 14%2Asqrt%283%29 cm.


The radius of the sphere is  r = 7%2Asqrt%283%29 cm.



The volume of the sphere is  %284%2F3%29%2Api%2Ar%5E3 = %284%2F3%29%2A3.14%2A%287%2Asqrt%283%29%29%5E3 = 7461.81 cm^3



The volume of the non-occupied part of the sphere is


    7461.81 - 2744 = 4717.81 cm^3.      ANSWER

Solved.