SOLUTION: The area of a cross-section parallel to the base of a cone is 30, and the area of the base of the cone is 67.5. If the altitude of the cone is 6, then find the ratio of volumes be
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-> SOLUTION: The area of a cross-section parallel to the base of a cone is 30, and the area of the base of the cone is 67.5. If the altitude of the cone is 6, then find the ratio of volumes be
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Question 1158312: The area of a cross-section parallel to the base of a cone is 30, and the area of the base of the cone is 67.5. If the altitude of the cone is 6, then find the ratio of volumes between the top cone and the frustum. Found 2 solutions by ankor@dixie-net.com, greenestamps:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Area of a cross-section parallel to the base of a cone is 30, and the area of the base of the cone is 67.5.
If the altitude of the cone is 6, then find the ratio of volumes between the top cone and the frustum.
:
Find the total volume of the cone
V = *67.5*6
V = 135 cu/units
:
Find the radius of the base
R^2 =
R^2 = 21.486
R =
R = 4.6353 is the Radius
:
Find the radius of the cross section
r^2 =
r^2 = 9.549
r = 3.09 is the small radius
:
The volume of a frustrum
V = 1.0472*h(R^2 + Rr + r^2)
V = 1.0472*h(21.486 + (4.6353*3.09) + 9.549)
V = 1.0472*h*45.358
V = 47.5h is the vol of the frustrum
:
The height of the small cone = (6-h)
Volume of the small cone
v =
v = 10(6-h)
v = 60 - 10h is the volume of the small cone
:
Vol of frustrum + vol of the cone = 135
47.5h + (60-10h) = 135
47.5h - 10h = 135 - 60
37.5h = 75
h = 75/37.5
h = 2 is the height of the frustrum
then
6-2 = 4 is the height of the small cone above the frustrum
:
The volume of the cone
v =
v = 40 cu/units
the volume of the frustrum
V = 47.5h
V = 47.5*2
V = 95 cu/units
:
"find the ratio of volumes between the top cone and the frustum." =