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Question 1025591: Hi, Dear All Gems,
I Thank you, Fombitz(26269) for your valuable information.
My question - previous post question number
Question 1025446:
how many nos. of spherical balls with dia "d" can be placed in a layer of circular tank with dia. D ?
thanks
Here I am again little bit elaborating the same question (Question 1025446)
Tank is filled with water up to certain level not fully, when we place Spherical (PP)balls in to the tank
How many number of balls are required to form a layer above the liquid level?
Say
Tank dia. = 16000 mm
Spherical (PP) ball dia. = 50 mm
How many number of balls will be there at top of the liquid? To form a single layer/stack
Thank you.
Regards,
Pothula
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! This is a very complicated question which is even more complex than your previous question.
First step is to determine the first level arrangement which is difficult.
The next step is to determine the second level arrangement based on the first level arrangement which is even more difficult.
The remaining levels can be copies of the first and second level so that step is more straightforward.
You also need to keep track of the volume of spheres, the original volume of water in the tank, and the updated volume of (spheres and water) to know when to stop adding spheres.
The top level of spheres will either be a copy of the first level or the second level so that step is straightforward once you've determine the level arrangements.
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Is this is research topic, homework problem, or an experiment you're setting up?
Also what level of school is this?
Are you looking for closed form solution or approximation?
This would require computer simulation to determine a solution, I believe.
Based on your responses, we could determine what the next step could be.
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