SOLUTION: An error of 2% was made in measuring the radius of a sphere. Find the approximate sorrespong percentage error the mesuring of irts volume.
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Question 1017821: An error of 2% was made in measuring the radius of a sphere. Find the approximate sorrespong percentage error the mesuring of irts volume.
THANK YOU Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! It will be a function of the cube.
As an example, suppose the actual radius is 1, but the error makes it 0.98 or 1.02
the cube of those two numbers differing from 1 will be the volume error, (0.94 to 1.06) or about 6%.
