You can put this solution on YOUR website! |x^2+x|=12
Solve for x.
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Tip: |a| = b when a = b or a = -b
In your case,
x^2 + x = 12 or x^2 + x = -12
I'll solve the first case for you:
x^2 + x = 12
x^2 + x - 12 = 0
(x + 4)(x - 3) = 0
x + 4 = 0 or x - 3 = 0
x = - 4 or x = 3
You will solve the second case same as above.
Hope it helps! John