Let the numbers be
A, B, C, D, E
from smallest to largest, i.e., A < B < C < D < E
We want E to be smallest possible.
= 9
Multiply through by 5
A + B + C + D + E = 45
Since the median is 7, C = 7
A + B + 7 + D + E = 45
To make E the smallest, we have to make A and B
as large as possible. But they have to be less
than median C = 7. So we choose A = 5 and B = 6.
5 + 6 + 7 + D + E = 45
18 + D + E = 45
E = 27 - D
E is smallest possible when D is the largest possible,
so that we subtract the most possible from 27:
But E > D, or
27 - D > D
27 > 2D
13.5 > D
So D is the largest value posible when D = 13
So E is smallest when E = 27 - 13 = 14
The 5 numbers are
5, 6, 7, 13, 14.
and 14 is the least possible value for the
largest number in the set.
Edwin