SOLUTION: four empty trucks are on a bridge that has a maximum capacity of 30,000 pounds. If the average (arithmetic mean) weight of three of the trucks is 7,800 pounds, what is the greatest

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Question 326175: four empty trucks are on a bridge that has a maximum capacity of 30,000 pounds. If the average (arithmetic mean) weight of three of the trucks is 7,800 pounds, what is the greatest possible safe weight of the fourth truck?
Found 2 solutions by checkley77, nyc_function:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
3*7,800+x=30,000
23,400+x=30,000
x=30,000-23,400
x=6,600 pounds for the 4 th. truck.

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
30,000- 3(7800) = 6600