.
Let v be the speed of the boat in still water, in miles per hour.
Then the effective rate traveling downstream is (v+5) mph;
the effective rate traveling upstream is (v-5) mph.
The "time" equation is
=
,
according to the condition.
To solve it, cancel the factor 44 in both side, first. You will get
=
.
Cross multiply and simplify
2*(v-5) = v+5
2v - 10 = v + 5
v = 15.
ANSWER. The boat rate in still water is 15 miles per hour.
Solved.