SOLUTION: david and daniel have a total of 120 coins.liz and maria total have 153 coins.david an d liz have total of 127 coins.how many coins do daniel and maria have together

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Question 1142769: david and daniel have a total of 120 coins.liz and maria total have 153 coins.david an d liz have total of 127 coins.how many coins do daniel and maria have together
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39629) About Me  (Show Source):
You can put this solution on YOUR website!
david  daniel  liz  maria
  v      n       z   m


system%28v%2Bn=120%2Cz%2Bm=153%2Cv%2Bz=127%29
find n+m.

adding first two equations
v%2Bn%2Bz%2Bm=120%2B153
n%2Bm%2Bv%2Bz=273
n%2Bm=273-%28v%2Bz%29
n%2Bm=273-127
highlight%28n%2Bm=146%29

Answer by ikleyn(52874) About Me  (Show Source):
You can put this solution on YOUR website!
.

            I will solve the problem combining grouping and re-grouping. 


Daniel + Maria = Daniel + Maria + David + Liz - (David + Liz) = (Daniel + David) + (Liz + Maria) - (David + Liz) = 120 + 153 - 127 = 146.    


ANSWER.  Daniel and Maria have together 146 coins.

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The problem can be solved and the solution can be presented by other ways, too;

but all these solutions/ways orbit around the same idea.