Question 1073696: Find the mean and median for each of the two samples, the. Compare the two sets of results.
T: 3,6,1,1,10,7,3,11,1,1
D: 4,3,3,3,2,2,1,3,3,4
Answer by KMST(5328)   (Show Source):
You can put this solution on YOUR website! The mean is the average.
The median if a value such that
half the sample is at least that much,
and the other half is no more than that.
To find it you just line up the values smallest to greatest, and look for the middle.
If there is an odd number of values, you take the value in the middle.
If there is an even number of values, you average the two values in the middle.
T: The mean is
From smallest to greatest the values are
1, 1, 1, 1, 3, 3, 6, 7, 10, 11.
Of those ten values, the 4th and 5th (the ones in the middle)
are 3, and 3, whose average is  , and that is the median.
D: The mean is
From smallest to greatest the values are
1, 2, 2, 3, 3, 3, 3, 3, 4, 4.
Of those ten values, the 4th and 5th (the ones in the middle)
are 3, and 3, whose average is , and that is the median.
For sets D and T, the median is the same, but the means are different.
Individually, the mean and the median do not tell the whole story.
Mean and median give you different information about a set of values.
Taken together, they give you a little more information, but still not the whole story.
The values in set D are more evenly spaced, and that makes mean and median to be close together.
The numbers in set T with a median of 3, but a higher mean pf 4.4 tell you that the mean is skewed higher by a few numbers higher than the rest.
You might suspect that there are a one or two very high values much higher than the mean and median,
but would not know how widely values range.
The same mean and median as for T would be found for
U: 3, 3, 3, 3, 3, 3, 6, 6, 7, 7 , or
V: 3, 3, 3, 3, 3, 3, 3, 3, 3, 17 .
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