SOLUTION: m∠K = (6x + 12)°. Find the measure of complement of ∠K. Options: (102 + 6x)° (112 + 6x)° (78 − 6x)° OR (67 − 6x)°

Algebra ->  Angles -> SOLUTION: m∠K = (6x + 12)°. Find the measure of complement of ∠K. Options: (102 + 6x)° (112 + 6x)° (78 − 6x)° OR (67 − 6x)°       Log On


   

Question 903041: m∠K = (6x + 12)°. Find the measure of complement of ∠K.
Options:
(102 + 6x)°
(112 + 6x)°
(78 − 6x)°
OR
(67 − 6x)°

Found 2 solutions by ewatrrr, Fombitz:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
90° - (6x+12)°= (78-6x)°

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complementary angles sum to 90.
K%2BC=90
6x%2B12%2BC=90
C=78-6x