SOLUTION: the clock reads 8:09, what is the exact measure of the angle formed by the hour and minute hands? Assume that each hands move continuously at a constant rate. Thus, in any given fr

Algebra ->  Angles -> SOLUTION: the clock reads 8:09, what is the exact measure of the angle formed by the hour and minute hands? Assume that each hands move continuously at a constant rate. Thus, in any given fr      Log On


   



Question 827842: the clock reads 8:09, what is the exact measure of the angle formed by the hour and minute hands? Assume that each hands move continuously at a constant rate. Thus, in any given fractional part of an hour, each hand will move that same fractional part of an hour's worth of movement.
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Your objectives are find where the minute hand points and where the hour hand points.

Using 0 degrees for the "12" position, the minute hand showing "9" is moved (9/60)*360 degrees from the "12".
This is 54 degrees from the "12".

The count of 8 hour is a little different. We focus on how far the hand has rotated from the 8 to the 9 marks. This is (9/60)(360) of the way from 8 to 9 on the clock face. "8" is (8/12)*360 degrees and "9" is (9/12)*360 degrees.
That is (2/3)360 and (3/4)360;
which is 240 and 270 degrees from "12". This is a difference of 30 degrees.
What is 9/60 of 30 degrees? It is (9/60)(30)=4.5 degree.
The hour hand points to 240+4.5 degrees from the "12".
The hour hand points to 244.5 degrees from the "12".

NEARLY DONE: Now you put these together.
Minute hand 54 degrees from the "12", and hour hand 244.5 degrees from the "12"