SOLUTION: The sum of two supplementary angles exceeds the difference of their measures by 116 degrees. Find the measures of each angle.

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Question 647714: The sum of two supplementary angles exceeds the difference of their measures by 116 degrees. Find the measures of each angle.

Found 2 solutions by DrBeeee, MathLover1:
Answer by DrBeeee(684) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = one angle
Let b = the other
From the problem statement we have
(1) a + b = 180
and
(2) (a+b) - (a-b) = 116
Simplifying (2) we get
(3) 2*b = 116, or
(4) b = 58
Then from (1) we get
(5) a = 122
Let's use (2) to check our answer.
Is ((122+58) - (122-58) = 116)?
Is (180 - 64 = 116)?
Is (116 = 116)? Yes
Answer: The two angles are 122 degrees and 58 degrees.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

supplementary angles, because they add up to 180°
so, alpha%2Bbeta=180....1
so, alpha-beta....the difference
given: the sum of two supplementary angles exceeds the difference of their measures by 116 degrees.
alpha%2Bbeta=alpha-beta%2B116....2...solve for beta
cross%28alpha%29%2Bbeta=cross%28alpha%29-beta%2B116
beta=-beta%2B116
beta%2Bbeta=116
2%2Abeta=116
beta=116%2F2
beta=58
now find alpha
alpha%2Bbeta=180....1
alpha=180-beta
alpha=180-58
alpha=122