SOLUTION: Please Help me on this problem. Three times the complement of an angle less the supplement of an angle is 10. find the supplement. I've started. 3c-s=10 3(90-x)

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Question 557142: Please Help me on this problem.
Three times the complement of an angle less the supplement of an angle is 10. find the supplement.
I've started.
3c-s=10
3(90-x) - 180 - x =10
270-3x-180-x=10
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Three times the complement of an angle less the supplement of an angle is 10. find the supplement.
I've started.
3c-s=10
3(90-x) - 180 - x =10
You should put the supplement in brackets
270 - 3x - (180 - x) = 10;
which will remind you to change the sign of x
270 - 3x - 180 + x = 10
combine like terms
-3x + x + 270 - 180 = 10
-2x + 90 = 10
-2x = 10 - 90
-2x = - 80
x =
x = +40
:
:
Check solution in original equation
3(90-40) - (180-40) =
3(50) - 140 = 10; confirms our solution of x = 40

SOLUTION: Please Help me on this problem. Three times the complement of an angle less the supplement of an angle is 10. find the supplement. I've started. 3c-s=10 3(90-x) - 180 -