Question 350248: An angle is 6 more than twice its complement. Find the measure of each angle. Found 2 solutions by Fombitz, ewatrrr:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Hi again.
as to your consecutive integers(differ by 1) let them be n,(n+1), (n+2)
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find three consecutive integers such that the sum of the first and third is 33 more than the second?
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Write as You read. solve for n and list all three n, (n + 1) and (n+2)
n + (n +2) = (n + 1) +33
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Hi.
*Note: sum of complementary angles is equal to 90 degrees.
Let n and (2n + 6) represent the two angles
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n + (2n + 6)= 90
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simplify and solve
3n = 84
n = 28
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(2n +6) = (56 +6) = 62
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28 degrees and 62 degrees are the angles
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Check your answer
28 + 62 = 90
