SOLUTION: tickets for a concert cost $5 $3 and $2.tiwce as many $5 tickets were sold as $2 tickets the receipts for 750 tickets were $2.625 how many of each price ticket were solde? thankyo

Algebra ->  Angles -> SOLUTION: tickets for a concert cost $5 $3 and $2.tiwce as many $5 tickets were sold as $2 tickets the receipts for 750 tickets were $2.625 how many of each price ticket were solde? thankyo      Log On


   



Question 322509: tickets for a concert cost $5 $3 and $2.tiwce as many $5 tickets were sold as $2 tickets the receipts for 750 tickets were $2.625 how many of each price ticket were solde?
thankyou

Answer by QH(50) About Me  (Show Source):
You can put this solution on YOUR website!
First set up your variables.
$2 Tix = x
$3 Tix = (750-3x) <--- Total tickets minus the sum of $2 & $5 tickets
$5 Tix = 2x
Now multiply the variables by their value and add together to = the total value of the tickets (2625).
$2 Tix = 2(x)
$3 Tix = 3(750-3x)
$5 Tix = 5(2x)
2x%2B2250-9x%2B10x=2625
3x%2B2250=2625
3x=375
x=125 ($2)
2x=250 ($5)
750-3x=375 ($3)
*check*
number of tix...
125%2B250%2B375=750
750=750
cost of tix...
%282%2A125%29%2B%285%2A250%29%2B%283%2A375%29=2625%0D%0A%7B%7B%7B250%2B1250%2B1125%2B2625
2625=2625