SOLUTION: I Have a triangle ABC. BAC=5x+8 ABC=6x+22 and BCA=3x-25...Now inside that triangle each corner has a lable of 1,2 and 3. I have to find each one of those angle and solve for x. Can

Algebra ->  Angles -> SOLUTION: I Have a triangle ABC. BAC=5x+8 ABC=6x+22 and BCA=3x-25...Now inside that triangle each corner has a lable of 1,2 and 3. I have to find each one of those angle and solve for x. Can      Log On


   

Question 231380: I Have a triangle ABC. BAC=5x+8 ABC=6x+22 and BCA=3x-25...Now inside that triangle each corner has a lable of 1,2 and 3. I have to find each one of those angle and solve for x. Can you help me? I don't fully understand how i go at doing this problem.
Thank you!!
Found 2 solutions by rfer, Earlsdon:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
5x+8+6x+22+3x-25=180
14x=175
x=12.5
5x+8=70.5 degrees
6x+22=97 degrees
3x-25=12.5 degrees

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Your triangle has three angles, BAC=5x+8, ABC=6x+22, and BCA=3x-25, and, as in any other triangle, the sum of these three angles is 180 degrees.
So, we can write an equation from the information given about each of these three angles:
%285x%2B8%29%2B%286x%2B22%29%2B%283x-25%29+=+180 Simplify this.
14x%2B5+=+180 Subtract 5 from both sides.
14x+=+175 Divide both sides by 14.
highlight_green%28x+=+12.5%29
The angles are:
BAC+=+5x%2B8
highlight%28BAC+=+70.5%29degrees.
ABC+=+6x%2B22
highlight%28ABC+=+97%29degrees.
BCA+=+3x-25
highlight%28BCA+=+12.5%29degrees.