SOLUTION: how can I slove these problems? <A is three times as large as its supplement, <B <A is one eigth as large as its complement, <B So can you help me please?

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Question 221067: how can I slove these problems?
So can you help me please?
Thank you in advance :)
Found 3 solutions by Alan3354, rapaljer, stanbon:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
A = 3B
A + B = 180
3B + B = 180
4B = 180
B = 45�
A = 135�
-------------
B = 8A
A + B = 90
A + 8A = 90
9A = 90
A = 10�
B = 80�

Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website!
Let x = angle B
3x= angle A, the supplement of angle B

x + 3x= 180
4x=180
x=45 degrees Angle B
3x = 135 degrees Angle A

Check: 45+135 = 180

R^2

Dr. Robert J. Rapalje

Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
< A is three times as large as its supplement, < B
---
< A = 3< B
< B = 180-< A
----------------
Substitute for < A and solve for < B
< B = 180-3< B
4< B = 180
< B = 45 Degrees
---
Solve for < A
< A = 3(45) = 135 degrees
=========================================
< A is one eigth as large as its complement, < B
< B = 90- < A = 8< B
------------------
Substitute for < B = 90-8< B
9< B = 90
< B = 10 degrees
--------
< A = 8(10) = 90 degrees
============================
Cheers,
Stan H.