SOLUTION: The question is AOB, COD are right angles with OC in the interior of angleAOB and OB in the interior of angleCOD. OX is the bisector of angleAOC and OY is the bidsector of angleBOD

Algebra ->  Angles -> SOLUTION: The question is AOB, COD are right angles with OC in the interior of angleAOB and OB in the interior of angleCOD. OX is the bisector of angleAOC and OY is the bidsector of angleBOD      Log On


   

Question 174747: The question is AOB, COD are right angles with OC in the interior of angleAOB and OB in the interior of angleCOD. OX is the bisector of angleAOC and OY is the bidsector of angleBOD. Can you prove that: angleAOX = angleBOY?
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the measure of AOX. Then COX is also x. Since AOB is 90, then BOC = 90 - 2x. Since COD is also 90, then BOD = 90 - (90 - 2x) = 2x. Finally, BOY is half that, or x. Therefore, since AOX and BOY are both x, then AOX = BOY. w%5E5which was what we wanted