SOLUTION: mo bisects < amb , m< amo = 7x-3 and m< bmo = 2x+12 solve for x and find m < amb

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Question 1205317: mo bisects < amb , m< amo = 7x-3 and m< bmo = 2x+12 solve for x and find m < amb
Found 2 solutions by MathLover1, Edwin McCravy:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

mo bisects <amb
to bisect an angle means to divide it in two equal parts

so, m<amo =m<bmo and m<amb=m<amo +m<bmo+

if
m<amo+=+7x-3+and m<bmo+=+2x%2B12 , we have
7x-3=+2x%2B12......solve for x+
7x-2x=+3%2B12
5x=+15
x=3

then
m<amo+=+7x-3+=7%2A3-3=21-3=18
and m<bmo+=+2x%2B12=2%2A3%2B12=18
then
m<amb=18%2B18=36


Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Always skip a space after < because if you don't it will be considered the
beginning of an HTML tag, and delete what follows it.


     A   
    /             The two bisectors of an angle have equal measures.  So,
   /7x-3
 M/_____O            7x - 3 = 2x - 12    <--you solve that
  \
   \2x+12 
    \
     B

Edwin