SOLUTION: The period P (in seconds) of a pendulum is given a function P=2π √(L/32), where L is the pendulum based on the length (in feet). A pendulum has a period of 4 seconds. Is th

Algebra ->  Angles -> SOLUTION: The period P (in seconds) of a pendulum is given a function P=2π √(L/32), where L is the pendulum based on the length (in feet). A pendulum has a period of 4 seconds. Is th      Log On


   

Question 1193387: The period P (in seconds) of a
pendulum is given a function
P=2π √(L/32), where L is the
pendulum based on the length
(in feet). A pendulum has a
period of 4 seconds. Is this a
pendulum twice as long as a
pendulum with period of 2
seconds?
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
The period P (in seconds) of a pendulum is given by a function P=2π √(L/32), where L is the pendulum length (in feet).
A pendulum has a period of 4 seconds.
Is this pendulum twice as long as a pendulum with period of 2 seconds?
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From the given formula, the length of the pendulum in feet is

    L = 32%2A%28P%2F%282%2Api%29%29%5E2.



If the period P is 4 seconds, then the length of the pendulum is

    L(4) = 32%2A%284%2F%282%2A3.14%29%29%5E2 = 12.98 feet (approximately).



If the period P is 2 seconds, then the length of the pendulum is

    L(2) = 32%2A%282%2F%282%2A3.14%29%29%5E2 = 3.25 feet (approximately).



Is the length L(4) twice as long as the length L(2) ?  - No.   The length L(4) is four times the length L(2).    ANSWER

Solved.