SOLUTION: A coin bank for donations for the protection of the reef contained ₱1570. There were twice as many ₱5-coins as ₱10-
coins, and 14 less ₱1-coins as ₱5-coins. How many of
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-> SOLUTION: A coin bank for donations for the protection of the reef contained ₱1570. There were twice as many ₱5-coins as ₱10-
coins, and 14 less ₱1-coins as ₱5-coins. How many of
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Question 1192213: A coin bank for donations for the protection of the reef contained ₱1570. There were twice as many ₱5-coins as ₱10-
coins, and 14 less ₱1-coins as ₱5-coins. How many of each kind were there? Answer by ikleyn(52778) (Show Source):
You can put this solution on YOUR website! .
A coin bank for donations for the protection of the reef contained ₱1570. There were twice as many ₱5-coins as ₱10-
coins, and 14 less ₱1-coins as ₱5-coins. How many of each kind were there?
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Let x be the number of P10-coins.
Then the number of P5-coins is 2x and the number of P1-coins is (2x-14).
Now write the total money equation
10x + 5*(2x) + 1*(2x-14) = 1570.
Simplify and find x
10x + 10x + 2x - 14 = 1570
22x = 1570 + 14
22x = 1584
x = 1584/22 = 72.
ANSWER. There are 72 P10-coins; 722*2 = 144 P5-coins and 144 - 14 = 130 P1-coins.
CHECK. 10*72 + 5*144 + 130 = 1570, total money. ! Correct !