SOLUTION: Show that (a) (sec^4-1)/(tan^2x) =2tan^2x (b) (cosec^4x -1)/(cot^2x) =2+cot^2x (c) (1+sec@)/(sin@+tan@)=cosec@ (d) (cos^3@-sin^2@)/(cos@-sin@)=1+sin@cos@ (e) (1-(sin@-cos@)^

Algebra ->  Angles -> SOLUTION: Show that (a) (sec^4-1)/(tan^2x) =2tan^2x (b) (cosec^4x -1)/(cot^2x) =2+cot^2x (c) (1+sec@)/(sin@+tan@)=cosec@ (d) (cos^3@-sin^2@)/(cos@-sin@)=1+sin@cos@ (e) (1-(sin@-cos@)^      Log On


   



Question 1140527: Show that
(a) (sec^4-1)/(tan^2x) =2tan^2x
(b) (cosec^4x -1)/(cot^2x) =2+cot^2x
(c) (1+sec@)/(sin@+tan@)=cosec@
(d) (cos^3@-sin^2@)/(cos@-sin@)=1+sin@cos@
(e) (1-(sin@-cos@)^2/sin@=2cos@

Found 2 solutions by Edwin McCravy, MathTherapy:
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
The limit is two problems.  I'll do a) and d), the ones
which are NOT identities because they were copied wrong:

(a) (sec^4-1)/(tan^2x) =2tan^2x 

The x was left off in the first term and the right side should be tan^4x

%28sec%5E4%28x%29-1%29%2F%28tan%5E2%28x%29%29+=tan%5E4%28x%29

Factor the numerator as the difference of squares A%5E2-B%5E2=%28A-B%29%28A%2BB%29



Then we use the identity 1%2Btan%5E2%28theta%29=sec%5E2%28theta%29 rewritten as
this: sec%5E2%28theta%29-1=tan%5E2%28theta%29





tan%5E2%28x%29%5E%22%22%28sec%5E2%28x%29%5E%22%22-1%29+=tan%5E4%28x%29

Use the identity  sec%5E2%28theta%29-1=tan%5E2%28theta%29 again:

tan%5E2%28x%29tan%5E2%28x%29+=tan%5E4%28x%29

tan%5E4%28x%29=tan%5E4%28x%29

------------------------------------

For (d)   

(d) (cos^3@-sin^2@)/(cos@-sin@)=1+sin@cos@

the sin^2@ should be sin^3@.

(d) 

The top on the left side is the difference of cubes, and
you should remember from algebra that the difference of
cubes factors according to this rule: A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29

So the numerator factors as

(d) 

   

  

  

Now use the identity cos%5E2%28theta%29%2Bsin%5E2%28theta%29=1 to make
the left side equal to the right side.

Edwin

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Show that
(a) (sec^4-1)/(tan^2x) =2tan^2x
(b) (cosec^4x -1)/(cot^2x) =2+cot^2x
(c) (1+sec@)/(sin@+tan@)=cosec@
(d) (cos^3@-sin^2@)/(cos@-sin@)=1+sin@cos@
(e) (1-(sin@-cos@)^2/sin@=2cos@
(a) should be: 
We'll focus on the left-side: