The limit is two problems. I'll do a) and d), the ones
which are NOT identities because they were copied wrong:
(a) (sec^4-1)/(tan^2x) =2tan^2x
The x was left off in the first term and the right side should be tan^4x
Factor the numerator as the difference of squares
Then we use the identity rewritten as
this:
Use the identity again:
------------------------------------
For (d)
(d) (cos^3@-sin^2@)/(cos@-sin@)=1+sin@cos@
the sin^2@ should be sin^3@.
(d)
The top on the left side is the difference of cubes, and
you should remember from algebra that the difference of
cubes factors according to this rule:
So the numerator factors as
(d)
Now use the identity to make
the left side equal to the right side.
Edwin
You can put this solution on YOUR website!
Show that
(a) (sec^4-1)/(tan^2x) =2tan^2x
(b) (cosec^4x -1)/(cot^2x) =2+cot^2x
(c) (1+sec@)/(sin@+tan@)=cosec@
(d) (cos^3@-sin^2@)/(cos@-sin@)=1+sin@cos@
(e) (1-(sin@-cos@)^2/sin@=2cos@