Question 101098: Find the length, slope, midpoint and equation to the line
PQ.
P (7, 11)
Q(-2,4) Found 2 solutions by checkley71, edjones:Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! slpe=(11-4)/(7+2)=7/9 is the slope.
noqw replace x & y in the line formula [Y=mX+b] WHERE m=SLOPE & b=INTERCEPT.
4=-2(7/9)+b
4=-14/9+b
b=4+14/9
b=(28+14)/9
b=42/9 NOW REDUCE BU DIVIDING BY 3
b=14/3 OR 4 2/3 ANSWER FOR THE Y INTERCEPT.
THUS THE LINE EQUATION THROUGH THESE 2 POINTS IS:
Y=7X/9+42/9.
You can put this solution on YOUR website! P (7, 11)
Q(-2,4)
distance=
.
slope=m=change in y/chnge in x=7/9
.
midpoint= ((7+(-2))/2,(11+4)/2)=(5/2,15/2)
.
equation: y-y[1]=m(x-x[1]
y-4=7/9(x-(-2))
y-4=7/9(x+2)
9y-36=7(x+2)
9y-36=7x+14
9y=7x+50
y=7x/9+50/9 slope-intercept form
7x-9y+50=0 general form
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