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Tutors Answer Your Questions about Angles (FREE)
Question 1186313: A triangular lot ABC with BC=400m and B=50° is divided into two parts by the line DE=150m which is parallel to BC. Point D and E are located on the side of AB and AC, respectively. The area of the segment BCED is 50,977 sq.m.
a. Find the angle that the side AC makes with the side BC
b. Find the area of ABC
c. Find the area of ADE
Click here to see answer by CPhill(1959)  |
Question 1191303: Complete the formal proof of the following theorem.
The bisectors of two adjacent supplementary angles form a right angle.
There is a line and three rays. There are six labeled points and four labeled angles.
Line A D is horizontal. B is on this line and between A and D.
Ray B C goes up and to the right.
Ray B F goes up and to the right. Point F is below and to the right of point C.
Ray B E goes up and to the left.
Angle A B E is labeled 1 and is marked with one arc.
Angle C B E is labeled 2 and is marked with one arc.
Angle C B F is labeled 3 and is marked with two arcs.
Angle D B F is labeled 4 and is marked with two arcs.
Given:
∠ABC is supplementary to ∠CBD.
BE bisects ∠ABC.
BF bisects ∠CBD.
Prove: ∠EBF is a right angle.
Statements Reasons
1.
---Select---
1. Given
2.
---Select---
2. The sum of the measures of supplementary ∠s is 180°.
3. m∠ABC = m∠1 + m∠2;
---Select---
3.
---Select---
4.
---Select---
4. Substitution
5.
BE bisects ∠ABC;
BF bisects ∠CBD.
5.
---Select---
6.
---Select---
6. If a ray bisects an ∠, then two ∠s of = measure are formed.
7. m∠2 + m∠2 + m∠3 + m∠3 = 180° 7.
---Select---
8.
2 · m∠2 + 2 · m∠3 = 180°
8. Combine like terms.
9. m∠2 + m∠3 = 90° 9.
---Select---
10.
---Select---
10. Angle-Addition Postulate
11.
---Select---
11. Substitution
12.
---Select---
12.
---Select---
Click here to see answer by CPhill(1959)  |
Question 1191305: Complete the formal proof of the theorem.
If two line segments are congruent, then their midpoints separate these segments into four congruent segments.
Line segment A B is above line segment D C. The two segments appear to be the same length. Points M and N are the midpoints of segments A B and D C, respectively.
Given:
AB ≅ DC
M is the midpoint of AB.
N is the midpoint of DC.
Prove:
AM ≅ MB ≅ DN ≅ NC
Statements Reasons
1.
AB ≅ DC
1.
Given
Correct: Your answer is correct.
2.
AB = DC
Correct: Your answer is correct.
2. If segments are ≅, then they are = in length.
3. AB = AM + MB;
AM + MB = DN + NC
Incorrect: Your answer is incorrect.
3.
Given
Incorrect: Your answer is incorrect.
4.
AM = MB = DN = NC
Incorrect: Your answer is incorrect.
4. Substitution
5.
M is the midpoint of AB;
N is the midpoint of DC.
5.
Given
Correct: Your answer is correct.
6.
AM = MB and DN = NC
Correct: Your answer is correct.
6. The midpoint of a segment forms two segments = in measure.
7. AM + AM = DN + DN 7.
Substitution
Correct: Your answer is correct.
8.
2 · AM = 2 · DN
8. Combine like terms.
9. AM = DN 9.
Division Property of Equality
Correct: Your answer is correct.
10.
AM + MB = DN + NC
Incorrect: Your answer is incorrect.
10. Substitution
11.
AM ≅ MB ≅ DN ≅ NC
11.
If segments are = in length, then they are ≅.
Correct: Your answer is correct.
Click here to see answer by ikleyn(52778)  |
Question 1191305: Complete the formal proof of the theorem.
If two line segments are congruent, then their midpoints separate these segments into four congruent segments.
Line segment A B is above line segment D C. The two segments appear to be the same length. Points M and N are the midpoints of segments A B and D C, respectively.
Given:
AB ≅ DC
M is the midpoint of AB.
N is the midpoint of DC.
Prove:
AM ≅ MB ≅ DN ≅ NC
Statements Reasons
1.
AB ≅ DC
1.
Given
Correct: Your answer is correct.
2.
AB = DC
Correct: Your answer is correct.
2. If segments are ≅, then they are = in length.
3. AB = AM + MB;
AM + MB = DN + NC
Incorrect: Your answer is incorrect.
3.
Given
Incorrect: Your answer is incorrect.
4.
AM = MB = DN = NC
Incorrect: Your answer is incorrect.
4. Substitution
5.
M is the midpoint of AB;
N is the midpoint of DC.
5.
Given
Correct: Your answer is correct.
6.
AM = MB and DN = NC
Correct: Your answer is correct.
6. The midpoint of a segment forms two segments = in measure.
7. AM + AM = DN + DN 7.
Substitution
Correct: Your answer is correct.
8.
2 · AM = 2 · DN
8. Combine like terms.
9. AM = DN 9.
Division Property of Equality
Correct: Your answer is correct.
10.
AM + MB = DN + NC
Incorrect: Your answer is incorrect.
10. Substitution
11.
AM ≅ MB ≅ DN ≅ NC
11.
If segments are = in length, then they are ≅.
Correct: Your answer is correct.
Click here to see answer by CPhill(1959)  |
Question 1191300: Use the drawing in which
AC intersects DB
at point O to answer the question.
Two lines intersect at point O to form four angles.
Line A C goes from point A in the top left, through point O in the center, to point C in the bottom right.
Line D B goes from point D in the bottom left, through O on line A C, to point B in the top right.
The angle at the bottom, ∠C O D, is labeled 1.
The angle on the left, ∠D O A, is labeled 2.
The angle at the top, ∠A O B, is labeled 3.
The angle on the right, ∠B O C, is labeled 4.
If
m∠2 =
x
2
− 30
°
and
m∠3 =
x
3
+ 60
°
,
find x and m∠2 in degrees.
x =
m∠2 =
°
Need Help? Read It
Click here to see answer by ikleyn(52778)  |
Question 1191300: Use the drawing in which
AC intersects DB
at point O to answer the question.
Two lines intersect at point O to form four angles.
Line A C goes from point A in the top left, through point O in the center, to point C in the bottom right.
Line D B goes from point D in the bottom left, through O on line A C, to point B in the top right.
The angle at the bottom, ∠C O D, is labeled 1.
The angle on the left, ∠D O A, is labeled 2.
The angle at the top, ∠A O B, is labeled 3.
The angle on the right, ∠B O C, is labeled 4.
If
m∠2 =
x
2
− 30
°
and
m∠3 =
x
3
+ 60
°
,
find x and m∠2 in degrees.
x =
m∠2 =
°
Need Help? Read It
Click here to see answer by CPhill(1959)  |
Question 1186931: An isosceles triangle ABC, in which AB = BC = 6√2 and AC = 12 is folded along the altitude BD so that planes ABD and BDC form a right dihedral angle. Find the angle between side AB and its new
position.
Click here to see answer by yurtman(42) |
Question 1206694: line segment CE has two bisectors. the first line OR is a perpendicular bisector. what can you conclude about the second bisector, line ST?
A. ST is equal to OR
B. ST is perpendicular to CE
C. ST is equal to CE
D.ST is not perpendicular to CE
E.ST is perpendicular to OR
Click here to see answer by greenestamps(13200)  |
Question 1206694: line segment CE has two bisectors. the first line OR is a perpendicular bisector. what can you conclude about the second bisector, line ST?
A. ST is equal to OR
B. ST is perpendicular to CE
C. ST is equal to CE
D.ST is not perpendicular to CE
E.ST is perpendicular to OR
Click here to see answer by MathLover1(20849)  |
Question 1206203: n the figure below, ∠2 and ∠3 are _________ angles.https://lh5.googleusercontent.com/dtgoufHvg32Z3TDuBFe3fQufLm4tLHI6fIUzNLFd4hYDKZHG3UcbGX8jWkCDs8x9lv2TmBjwcgaamr71O3VKydNvJS4a1wmfrQTyfR48xvqkeyAPwSvpt--BZua4Z6BC4D3NnRt2p852TZKLDddW8eE
Click here to see answer by ikleyn(52778)  |
Question 1205141: from this given statement, select the definition, property, postulate, or theorem that justifies the prove statement.
given: angle ADP=CDP
Prove: PD is an angle bisector of angle ADC
A: corresponding parts of a congruent triangle are congruent
B: betweenness of rays
C: definition of an angle bisector
D: angle-side-angle
E: hypotenuse-leg
Click here to see answer by Edwin McCravy(20054)  |
Question 1204564: point P is not on line AB. line BV and FG both run through P and line AB. what can you conclude about line BV and line FG.
A. BV and FG cannot both be perpendicular to AB
B.BV and FG are congruent lines
C. BV and FG are perpendicular to each other
D.BV and FG are both perpendicular to AB
E.BV and FG intersect AB at the same point
Click here to see answer by greenestamps(13200)  |
Question 1204564: point P is not on line AB. line BV and FG both run through P and line AB. what can you conclude about line BV and line FG.
A. BV and FG cannot both be perpendicular to AB
B.BV and FG are congruent lines
C. BV and FG are perpendicular to each other
D.BV and FG are both perpendicular to AB
E.BV and FG intersect AB at the same point
Click here to see answer by MathLover1(20849)  |
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