Tutors Answer Your Questions about Linear Algebra (FREE)
Question 62946: The following table shows data for the city K that consist of i ts population during the time period from the year 1942 to the year 2002.
Scatter plotting
1940- 20,360
1950- 23,390
1960- 28,580
1970- 35,425
1980- 45,260
1990- 54,320
2000- 63,525
Find a qudratic model for the data.Round the values of a,b,and c to three significant digits?
Click here to see answer by stanbon(75887) |
Question 64945: Bettes Bananas delivers fresh bananas to your doorstep every morning. The cost for the service is $12/month flat rate and your first ten bananas are free! Further bananas cost $0.10 each. Construct a piecewise-linear function for the cost C of receiving N bananas in a month.
Click here to see answer by stanbon(75887) |
Question 65958: A bus leaves a station at 1 P.M., traveling west at an aver-age
rate of 44 mi/h. One hour later a second bus leaves the same station, traveling
east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
Click here to see answer by chitra(359) |
Question 65996: A common mistake when solving equations is the following:
The equation: 2(x -2) = x +3
First step in solving: 2x -2 =x +3
Write a clear explanation of what error has been made. What could be done to avoid this error?
Click here to see answer by uma(370) |
Question 66175: I'm not sure if this is Linear Algebra, but i have a good feeling. So:
Suppose Y varies directly with the square of W and the cube of X. When W=4 and X=2, Y=72. Find Y when W=1 and X=5.
I'm having problems setting the problem up and I don't know what it means when it says it varies directly with the (square, cube, etc..) of X (or whatever).
Much appricated thanks!
Click here to see answer by stanbon(75887) |
Question 66263: MS.SPEEDI IS PLANNING ON STARTING AT THE FINISH LINE AND WALKING TOWARD THE STARTING LINE WHEN THE RACE STARTS.IF SHE WALKS ONE METER PER SECOND AND MEETS DINA 11 SECONDS AFTER THE START OF THE RACE,HOW LONG IS THE RACE?
Click here to see answer by stanbon(75887) |
Question 66699: What is wrong with this arguement? Suppose x and y represent two real numbers, where x > y
2 > 1
2(y-x)> 1(y-x)
2y-2x>y-x
y-2x>-x
y>x
The final inequality, y>x, is impossible because we were initally given x>y.
Extra info in problem possibly the "arguement"...This is a true statement . Multiply both sides by y-x. Use the distribtive property . Subtract from both sides. Add 2x to both sides.
Click here to see answer by Nate(3500) |
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