SOLUTION: Find an equation of the line passing through point (-10, 3), and perpendicular to the line 2y+5x= 0, and express the result in slope intercept form.
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Question 993516: Find an equation of the line passing through point (-10, 3), and perpendicular to the line 2y+5x= 0, and express the result in slope intercept form. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Slope of the line 2y+5x=0 is
2y=-5x
y=-5x/2.
The line perpendicular to that has a slope of 2/5, the negative reciprocal of the above slope.
now use point slope formula
y-y1=(2/5)(x-x1)
y-3=(2/5)(x+10) (watch sign here)
y-3=2x/5+4
y=(2/5)x+7
