SOLUTION: I have tried to solve this I can't seem to get it set up right. The force needed to keep a car from skidding on a curve varies inversly as the radius of the curve and jointly as th

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Question 98500This question is from textbook Mathematical ideas
: I have tried to solve this I can't seem to get it set up right. The force needed to keep a car from skidding on a curve varies inversly as the radius of the curve and jointly as the weight of the car and the square of the speed If 242 pounds of force keep a 2000 pound car from skidding on a curve of radius 500 feet at 30 miles per hour, what force would keep the same car from skidding on a curve radius 750 feet at 50 miles per hour? This question is from textbook Mathematical ideas

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the speed
Force = %28car+weight+%2A+speed%5E2%29%2F%28curve+radius%29k
:
If 242 pounds of force keep a 2000 pound car from skidding on a curve of radius 500 feet at 30 miles per hour,
:
Find k
%282000%2A30%5E2%29%2F500k = 242
:
%282000%2A900%29%2F500k = 242
:
%281800000%29%2F500k = 242
:
3600k = 242
:
k = 242/3600
:
k = .0672
:
:
what force would keep the same car from skidding on a curve radius 750 feet at 50 miles per hour?
:
Using .0672 for k in the same formula
:
F = .0672%28%282000%2A50%5E2%29%2F750%29
:
F = .0672%28%282000%2A50%5E2%29%2F750%29
:
F = .0672%28%2850000000%29%2F750%29
:
F = .0672 * 6666.67
:
F = 448 lb