SOLUTION: There is a 20 ft wide and 2 ft long bulletin board. It's asking how many pieces of artwork of each size can she post if she's posting at least 16 pieces of artwork in a row. The si

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Question 937538: There is a 20 ft wide and 2 ft long bulletin board. It's asking how many pieces of artwork of each size can she post if she's posting at least 16 pieces of artwork in a row. The sizes are 11.5 in. wide and 12.5 in. long. The other size is 14 in wide and 18.5 in long. We're supposed to make an inequality and graph them to answer but I don't understand how. Help?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
There is a 20 ft wide and 2 ft long bulletin board. It's asking how many pieces of artwork of each size can she post if she's posting at least 16 pieces of artwork in a row. The sizes are 11.5 in. wide and 12.5 in. long. The other size is 14 in wide and 18.5 in long. We're supposed to make an inequality and graph them to answer but I don't understand how. Help?
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20 ft = 20*12 = 240 inches
2 ft = 24 inches
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Equations:
Quantity:: e + t >= 16
Width::: 11.5e + 12.5t <= 240
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Graph the equalities::
graph%28400%2C400%2C-10%2C30%2C-10%2C30%2C16-x%2C%28240-11.5x%29%2F12.5%29
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Note:: Solutions are above the lower line and below the upper line.
You need to find whole number solutions.
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Cheers,
Stan H.
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