Question 937321: solve the system:
X-2Y+3=0
Y^2=4X
The answers are (1,2) and (9,6).
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! x - 2y + 3 = 0
y^2 = 4x
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x = 2y - 3
y^2 = 4(2y - 3)
y^2 = 8y - 12
y^2 - 8y + 12 = 0
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the above quadratic equation is in standard form, with a=1, b=-8 and c=12
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 -8 12
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the quadratic has two real roots at:
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y = 6
y = 2
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y = 6
x = 2*6 - 3
x = 9
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y = 2
x = 2*2 - 3
x = 1
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answer:
x = 9
y = 6
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x = 1
y = 2
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