SOLUTION: If {{{x1 = (-b+sqrt(b^2-4ac))/2a}}} and {{{x2 = (-b-sqrt(b^2-4ac))/2a}}} are roots of an equation,form the equation?

Algebra ->  College  -> Linear Algebra -> SOLUTION: If {{{x1 = (-b+sqrt(b^2-4ac))/2a}}} and {{{x2 = (-b-sqrt(b^2-4ac))/2a}}} are roots of an equation,form the equation?       Log On


   

Question 896258: If x1+=+%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F2a and x2+=+%28-b-sqrt%28b%5E2-4ac%29%29%2F2a are roots of an equation,form the equation?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
They are roots of the equation ax%5E2+%2B+bx+%2B+c+=+0

Those two given solutions/roots are part of the quadratic formula. Often you'll see it in the "plus/minus" format, but it helps to break it up like that.