SOLUTION: Dear Math Tutor,
Simplify [(4x.1/2y^2)] / (2x^-1 y^2)
I simplified it to be: [16x^2. 1/4 y^2]/ (2/x . y^2}
so (16x^2)/1 x x/2 = 8x^3
1/4y^2 x 1/y^2 = 1/4y2
= 8x^3.1/4y^2
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-> SOLUTION: Dear Math Tutor,
Simplify [(4x.1/2y^2)] / (2x^-1 y^2)
I simplified it to be: [16x^2. 1/4 y^2]/ (2/x . y^2}
so (16x^2)/1 x x/2 = 8x^3
1/4y^2 x 1/y^2 = 1/4y2
= 8x^3.1/4y^2
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Question 879496: Dear Math Tutor,
Simplify [(4x.1/2y^2)] / (2x^-1 y^2)
I simplified it to be: [16x^2. 1/4 y^2]/ (2/x . y^2}
so (16x^2)/1 x x/2 = 8x^3
1/4y^2 x 1/y^2 = 1/4y2
= 8x^3.1/4y^2
Is that correct?
With gratitude,
Nat Answer by ewatrrr(24785) (Show Source):
