SOLUTION: The problem I am working on is for some reason just escaping me. It is 15x-4=6x+3

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Question 8548: The problem I am working on is for some reason just escaping me. It is
15x-4=6x+3

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
First, you must get all the x terms on one side. To get rid of the 6x on the right side, you can add -6x to each side:

15x - 4 = 6x + 3
15x -6x - 4 = 6x - 6x + 3
9x - 4 = 3

Next, you need to get all the "non-x" terms on the OTHER side. In this case, it will be nice to get rid of the -4, so you add +4 to each side:
9x - 4 = 3
9x -4 +4 = 3 + 4
9x = 7

The last step is to get the x by itself. To get rid of the 9, you must realize that the operation between the 9 and the x is multiplication, so you must undo multiplication--that is, divide both sides by 9.

+%289x%29%2F9=+7%2F9
x+=+7%2F9

It's ugly, but in math you just have to get used to ugly!! It happens all the time. Life doesn't always come out even!!

R^2 at SCC