SOLUTION: The period of a simple pendulum is directly proportional to the square root of its length. If a pendulum has a length of 6 feet and a period of 2 seconds, to what length should i

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Question 7540: The period of a simple pendulum is directly proportional to the
square root of its length. If a pendulum has a length of 6 feet and a
period of 2 seconds, to what length should it be shortened to achieve
a 1 second period?
Found 2 solutions by Earlsdon, Merhuza:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Write the proportion:
p+=+k%2Asqrt%28l%29 Substitute the given values of p (2 secs) and l (6 ft.) and solve for k.
2+=+k%2Asqrt%286%29
k+=+2%2Fsqrt%286%29 Now you can write:
sqrt%28l%29+=+p%2Fk Square both sides to find l.
l+=+%28p%2Fk%29%5E2 Now substitute the values for p+=%281+sec%29 and k+=2%2Fsqrt%286%29 then solve for l.
l+=+%281%2F%282%2Fsqrt%286%29%29%29%5E2
l+=+%28sqrt%286%29%2F2%29%5E2
l+=+6%2F4
l = 1.5 ft.

Answer by Merhuza(5) About Me  (Show Source):
You can put this solution on YOUR website!
l=6/4
=1.5ft