Question 747676: measured in grams and the time in hours. Since population P depends on time t and each input corresponds to exactly one output, we can say that population is a function of time; so P(t) represents the population at time t.
Time (hours), t
Population (grams), P
0
0.15
2.5
0.33
3.5
0.45
4.5
0.58
6
0.65
(a) Find the average rate of change of the population from 0 to 2.5 hours.
(b) Find the average rate of change of the population from 3.5 to 6 hours.
(c) What was happening to the average rate of change as time passes
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! measured in grams and the time in hours. Since population P depends on time t and each input corresponds to exactly one output, we can say that population is a function of time; so P(t) represents the population at time t.
Time (hours), t
Population (grams), P
0
0.15
2.5
0.33
3.5
0.45
4.5
0.58
6
0.65
(a) Find the average rate of change of the population from 0 to 2.5 hours.
(0.33-0.15)/(2.5-0) = 0.072 grams/hr
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(b) Find the average rate of change of the population from 3.5 to 6 hours.
(0.65-0.45)/(6-3.5) = 0.2/2.5 = 0.8 gramas/hr
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(c) What was happening to the average rate of change as time passes
The grams were being reduced at a higher rate.
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Cheers,
Stan H.
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