SOLUTION: I need to find the answer to and show the steps of these two equations but I have no clue what to do or where to start.It's part of a project which is a big portion of my grade, an

Algebra ->  College  -> Linear Algebra -> SOLUTION: I need to find the answer to and show the steps of these two equations but I have no clue what to do or where to start.It's part of a project which is a big portion of my grade, an      Log On


   

Question 739876: I need to find the answer to and show the steps of these two equations but I have no clue what to do or where to start.It's part of a project which is a big portion of my grade, any help would be great.
The equations are:
133(b)+6(c)=1000
2.07(b)+0.2(c)=8
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
133(b)+6(c)=1000
2.07(b)+0.2(c)=8

133b+6c=1000
2.07b+0.2c=8



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Solve equation 1 for 'c'

133b+6c=1000

6c=1000-133b

c=(1000-133b)/6

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Plug this into the second equation

2.07b+0.2c=8

2.07b+0.2( (1000-133b)/6 )=8

2.07b+(0.2*1000-0.2*133b)/6=8

2.07b+(200-26.6b)/6=8

6*2.07b+6*(200-26.6b)/6=6*8 ... Multiply EVERY term by the LCD 6 to clear out fractions

12.42b + 200 - 26.6b = 48

-14.18b + 200 = 48

-14.18b = 48 - 200

-14.18b = -152

b = -152/(-14.18)

b = 10.71932299 (this is approximate)

c = (1000-133b)/6

c = (1000-133*10.71932299)/6

c = (1000-1425.66995767)/6

c = -425.66995767/6

c = -70.944992945 (this is approximate too)

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So the approximate solutions are

b = 10.71932299

c = -70.944992945