SOLUTION: The cost (in dollars) of g gallons of gasoline and be modeled by C(g) = 2.25g. The gasoline used by an SUV can be modeled by g(d) = 0.025d where d is the distance (in miles). Find

Algebra ->  College  -> Linear Algebra -> SOLUTION: The cost (in dollars) of g gallons of gasoline and be modeled by C(g) = 2.25g. The gasoline used by an SUV can be modeled by g(d) = 0.025d where d is the distance (in miles). Find       Log On


   

Question 671373: The cost (in dollars) of g gallons of gasoline and be modeled by C(g) = 2.25g. The gasoline used by an SUV can be modeled by g(d) = 0.025d where d is the distance (in miles). Find C(g(d)). Evaluate C(g(500)). What does C(g((500)) represent?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The cost (in dollars) of g gallons of gasoline and be modeled by C(g) = 2.25g. The gasoline used by an SUV can be modeled by g(d) = 0.025d where d is the distance (in miles).
--------------------------
Find C(g(d)) = C[0.025d] = 2.25*0.025d = 0.05625d
------------------------------
Evaluate C(g(500)) = C[0.025*500] = C[12.5] = 2.25*12.5 = 28.125
-----------
What does C(g((500)) represent?
g(500) is the amt. of gasoline in gallons needed by an SUV to travel 500 miles.
Then C(12.5) = 2.25*12.5 = 28.125 is the cost in dollars for that 12.5
gallons of gasoline.
So C(g(500)) is the cost in dollars for an SUV to go 500 miles.
=======================
Cheers,
Stan H.