SOLUTION: The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field
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If the perimeter of the playing field is 230 ft, find the length and width of the field
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Question 65979: The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field
You can put this solution on YOUR website! Let the width of the field be x ft.
So length = (2x-5) ft
Perimeter = 2[ length + width]
==> 2[2x-5+x] = 230
==> 2{3x-5} = 230
==> 6x - 10 = 230
==> 6x - 10 + 10 = 230 + 10
==> 6x = 240
==> 6x/6 = 240/6
==> x = 40
Thus the width of the field = 40 ft.
Length = 2x-5
= 2*40 - 5
= 80 - 5
= 75
Width = 40 ft and length = 75 ft
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