SOLUTION: A bus leaves a station at 1 P.M., traveling west at an aver-age rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what

Algebra ->  College  -> Linear Algebra -> SOLUTION: A bus leaves a station at 1 P.M., traveling west at an aver-age rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what      Log On


   

Question 65958: A bus leaves a station at 1 P.M., traveling west at an aver-age
rate of 44 mi/h. One hour later a second bus leaves the same station, traveling
east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
We first calculate the average velocity of both the buses.

That is given by:


Average Velocity = %2844+%2B+48%29%2F2

= 46 milies/ hr


Therefore, total time taken to cover 274 miless by the two buses would be

= Distance%2FSpeed


= 274%2F46


= 5.95 hrs


Then there is a time gap of 1 hr for the 2nd bus to start from the initial position

Therefore,

5.95 + 1 = 6.95 hrs


Hence, the solution.