SOLUTION: S = n(a + l)/2 solve for l
The first thing I did was use distributive property for n(a + l). So then:
S = (na + nl)/2
Then, I thought about trying to cancel out the 2, lea
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-> SOLUTION: S = n(a + l)/2 solve for l
The first thing I did was use distributive property for n(a + l). So then:
S = (na + nl)/2
Then, I thought about trying to cancel out the 2, lea
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Question 653117: S = n(a + l)/2 solve for l
The first thing I did was use distributive property for n(a + l). So then:
S = (na + nl)/2
Then, I thought about trying to cancel out the 2, leaving it as:
2S = 2na + 2nl
Am I on the right track? Answer by Edwin McCravy(20055) (Show Source):
That "l" looks too much like the number "1", so I'm going to
use capital letters instead:
S = N(A + L)/2
Clear of fractions by multiplying both sides by 2
2S = 2N(A + L)/2
Then the 2's cancel on the right
2S = 2N(A + L)/2
and then we don't have any fractions:
2S = N(A + L)
Now remove the parentheses using the distributive principle:
2S = NA + NL
Now isolate the only term that contains L on the right by
subtracting NA from both sides:
2S - NA = NL
Finally we divide both sides by N which is the coefficient of L:
= L
And if you like you can turn the equation around and write it as
L =
Edwin
