SOLUTION: Matrices A, B, and C are given by A= open bracket 3, -2, 4/ 6 1 0/ -5 9 5 close bracket B= open bracket 1 5 0/ -8 4 7/ 2 3 -9 close bracket C= open bracket

Algebra ->  College  -> Linear Algebra -> SOLUTION: Matrices A, B, and C are given by A= open bracket 3, -2, 4/ 6 1 0/ -5 9 5 close bracket B= open bracket 1 5 0/ -8 4 7/ 2 3 -9 close bracket C= open bracket       Log On


   



Question 635548: Matrices A, B, and C are given by
A= open bracket 3, -2, 4/ 6 1 0/ -5 9 5 close bracket
B= open bracket 1 5 0/ -8 4 7/ 2 3 -9 close bracket
C= open bracket 3 -2 -7/ -4 5 1/ 3 0 6 close bracket
If D=A(2B+3C) find d(subscript) 23

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
First of all, this problem has nothing to do with Trigonometry. Please try to post your problems in a relevant category. You will get faster, better responses when problems are posted in the right categories.












If all you care about is d%5B23%5D then all you need to is multiply the 2nd row of the first matrix times the 3rd row of the second matrix:
d%5B23%5D+=+6%2A%28-21%29%2B1%2A17%2B0%2A0+=+-126+%2B+17+%2B+0+=+-109

Here's the full multiplication of the two matrices: