SOLUTION: Find the dimensions of a box whose area is 196 cu. in., whose surface area is 280 sq. in., and whose width is twice its height.

Algebra ->  College  -> Linear Algebra -> SOLUTION: Find the dimensions of a box whose area is 196 cu. in., whose surface area is 280 sq. in., and whose width is twice its height.      Log On


   

Question 59579: Find the dimensions of a box whose area is 196 cu. in., whose surface area is 280 sq. in., and whose width is twice its height.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the dimensions of a box whose area is 196 cu. in., whose surface area is 280 sq. in., and whose width is twice its height.
----------
Let height be "x"
Width = "2x"
Base and top have area (2x)^2 = 4x^2
Sides have area (2x)x=2x^2
Total area = top + bottom + 4(side)
=4x^2 + 4x^2+4(2x^2)
=16x^2
So, 16x^2=280 sq. in.
x^2=17.5
x=4.1833 inch
-----------
Checking:
Volumn = area of base * height
196 = (4x^2)(x)
49=x^3
x=3.659
-----------
Comment: Something is wrong in Denmark
Cheers,
Stan H.