SOLUTION: Talia plans to make tallitot(prayer shawls) and matching kipot(prayer hats) from a bolt of material. The fabric she plans to use is 250 yards long. She will need 2 yards of materia

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Question 59000: Talia plans to make tallitot(prayer shawls) and matching kipot(prayer hats) from a bolt of material. The fabric she plans to use is 250 yards long. She will need 2 yards of material for each tallitot(prayer shawl) and 1/6 of a yard for each kipah(prayer hat). She also plans to put tzitzit(fringes) on the tallit and will need 1 yard of cord for each tallit. The kipot will not have any fringes. She has 100 yards of cord to use for the tzitzit.
1. Please help me find the two equations to use to solve for how many kipot and tallitot she can make from the supplies on hand.t=tallipot and k=kipot.
I know that you have to have yards+yards=yards but i am confused to were the 100yards of fringe cord comes into play. Thank you very much i needed it!
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Talia plans to make tallitot(prayer shawls) and matching kipot(prayer hats) from a bolt of material. The fabric she plans to use is 250 yards long. She will need 2 yards of material for each tallitot(prayer shawl) and 1/6 of a yard for each kipah(prayer hat). She also plans to put tzitzit(fringes) on the tallit and will need 1 yard of cord for each tallit. The kipot will not have any fringes. She has 100 yards of cord to use for the tzitzit.
1. Please help me find the two equations to use to solve for how many kipot and tallitot she can make from the supplies on hand.t=tallipot and k=kipot.
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Let "s" be the number of shawls made.
Let "h" be the number of hats made.
EQUATIONS:
Material Inequality: 2s+(1/6)h<=250
Cord Inequality: s+(0)h<=100
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Cheers,
Stan H.