SOLUTION: I have already gotten this wrong on an exam, I need to know what the right answer is. What is the value of j in the equation? the square root of j+ the square root of j+14=3 to th

Algebra ->  College  -> Linear Algebra -> SOLUTION: I have already gotten this wrong on an exam, I need to know what the right answer is. What is the value of j in the equation? the square root of j+ the square root of j+14=3 to th      Log On


   



Question 5797: I have already gotten this wrong on an exam, I need to know what the right answer is. What is the value of j in the equation? the square root of j+ the square root of j+14=3 to the square root of j+10. This is also a multiple choice A.2 B.4 C.16 and D.the square root of 2? Please help?
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
you really must learn to use brackets - you confuse the hell of everyone by your "English" descriptiion of the maths question.

I am assuming (big assumption) that you mean the following:

sqrt%28j%29+%2B+sqrt%28j%29+%2B+14+=+3sqrt%28j%29+%2B+10? If so,

2sqrt%28j%29+%2B+14+=+3sqrt%28j%29+%2B+10
2sqrt%28j%29+%2B+4+=+3sqrt%28j%29
4+=+sqrt%28j%29
or ... sqrt%28j%29+=+4 --> square both sides to give j+=+4%5E2.

j = 16

jon.