Question 5679: What is the equation of the line that passes through the points (-2,2) and (0,5)? This is a multiple choice A. y=-3//2x+5 B.y=3/2x+5 C. y=x+5 D.y=x-5
Answer by lotanez(23)   (Show Source):
You can put this solution on YOUR website! The point-slope equation y=mx+b (which tells you how much y is changing for every so much that x changes)
m=slople, b=y-intercept (the point on the y-axis where the line toches or intercepts)
first you have to find the slope with the points given:
equation for slope is m = y2 - y1/x2 - x1
for points (-2,2) -2=x1 and 2=y1
for points (0,5) 0=x2 and 5=y2
m = 5-2/0-(-2) = 3/2
m = 3/2
when you have an x value that is zero, the y value is the b in the point-slope equation.
(graph out the points and you'll know what I mean)
therefore the y-intercept = 5 (because of the points given (0,5) so if
y-intercept=b, then b=5.
Now just fill in the equation:
y=mx+b
m=3/2
b=5
y=3/2x + 5
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